81c^2+18c+1=

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Solution for 81c^2+18c+1= equation:


Simplifying
81c2 + 18c + 1 = 0

Reorder the terms:
1 + 18c + 81c2 = 0

Solving
1 + 18c + 81c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(1 + 9c)(1 + 9c) = 0

Subproblem 1

Set the factor '(1 + 9c)' equal to zero and attempt to solve: Simplifying 1 + 9c = 0 Solving 1 + 9c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 9c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 9c = 0 + -1 9c = 0 + -1 Combine like terms: 0 + -1 = -1 9c = -1 Divide each side by '9'. c = -0.1111111111 Simplifying c = -0.1111111111

Subproblem 2

Set the factor '(1 + 9c)' equal to zero and attempt to solve: Simplifying 1 + 9c = 0 Solving 1 + 9c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 9c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 9c = 0 + -1 9c = 0 + -1 Combine like terms: 0 + -1 = -1 9c = -1 Divide each side by '9'. c = -0.1111111111 Simplifying c = -0.1111111111

Solution

c = {-0.1111111111, -0.1111111111}

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